citizenaspirant/PyBitmessage
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str() for luck

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nimda 2013-06-13 22:28:33 -04:00
parent e7378cffcc
commit e6beeedea1
1 changed files with 2 additions and 2 deletions
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src/bitmessageqt/__init__.py
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@ -1892,12 +1892,12 @@ class MyForm(QtGui.QMainWindow):
for i in range(len(self.ui.tableWidgetAddressBook.selectedIndexes())):
listOfSelectedRows[self.ui.tableWidgetAddressBook.selectedIndexes()[i].row()] = 0
for currentRow in listOfSelectedRows:
addressAtCurrentRow = self.ui.tableWidgetAddressBook.item(currentRow,1).text()
addressAtCurrentRow = str(self.ui.tableWidgetAddressBook.item(currentRow,1).text())
# Then subscribe to it... provided it's not already in the address book
if shared.isAddressInMySubscriptionsList(addressAtCurrentRow):
self.statusBar().showMessage(QtGui.QApplication.translate("MainWindow", "Error: You cannot add the same address to your subsciptions twice. Perhaps rename the existing one if you want."))
continue
labelAtCurrentRow = self.ui.tableWidgetAddressBook.item(currentRow,0).text()
labelAtCurrentRow = str(self.ui.tableWidgetAddressBook.item(currentRow,0).text())
self.addSubscription(labelAtCurrentRow, addressAtCurrentRow)
def on_context_menuAddressBook(self, point):
self.popMenuAddressBook.exec_( self.ui.tableWidgetAddressBook.mapToGlobal(point) )